8/20/2020 0 Comments B-H Curve Experiment Pdf
Given: 8 10 -4 Wb A 1000 mm 2 1000 10 -6 0.001 m 3 Total length of air gap, l g 2 0.2 0.4 mm 0.0004 m ( r ) c.s. 170 Example 14. A magnetic ring has a mean circumference of 1.8 m and is of 0.012 m 2 cross-section, and is wound with 210 turns.The magnetisation has many names being referred to as: B-H curve, the magnetic saturation curve, the virgin curve or simply the saturation curve.The difference in flux between the saturation curve and the air line, OA at any magnetising force,is due to the contribution of the magnetic material.This flux is known as the intrinsic flux and gives a true measure of magnetic properties than does the total flux, especially at very high m.m.fs, The point at which the intrinsic flux density curve becomes horizontal gives the intrinsic saturation.
The magnetisation curves can be determined by the following methods provided the materials are in the. The graphs in Fig. The data for mild steel, wrought iron and sheet steel are so similar that they can be represented by a common graph. Stalloy is an alloy of iron and silicon commonly used in the construction of transformers and A.C. Example 6. An air cored toroidal coil has 1500 turns and carries a current of 0.2 A The length of the magnetic circuit is 300 mm and cross-sectional area of the coil is 800 mm 2. Calculate: (i) Magnetic field strength, (ii) Flux density, and (iii) Total flux within the coil. Solution. Number of turns, N 1500 Current, I 0.2 A Length of the magnetic circuit, 1 300 mm 0.3 m Cross-sectional area of the coil, A 800 mm 2 800 10 -6 m 2 I. Magnetic field strength, H: III.Total Flux within the coil,: B A 1.256 10 -3 800 10 -6 1.005 10 -6 Wb. Ans.) Example 7. A coil of 300 turns and of resistance 10 is wound uniformly over a steel ring of mean circumference 30 cm and cross-sectional area 9 cm 2. It is connected to a supply at 20 V. D.C. If rollll IIIrlllcability of the ring is 1500, find: (i) The magnetising force, (ii) The reluctance, (iii) The m.m.f., and (iv) The flux. VTU, 1999) Solution, Given: N 300; R 10 Example 8. A magnetic circuit consists of an iron ring of mean circumference 80 cm with cross-sectional area of 12 cm 2 throughout. A current of 1 A in the magnetising coil of 200 turns produces a total flux of 1.2 m Wb in the iron. Calculate: I. The flux density in the iron, II. The reluctance of the circuit. Solution. Given: l 80 cm 0.8 m; a 12 cm 2 12 10 -4 m 2; 1 1 A; N 200; 1.2 mWb 0.0012 Wb, Example 9. An iron ring 200 mm mean diameter is made of 30 mm round iron of permeability 900, has an air gap 10 mm wide. It has 800 turns. If the current flowing through this winding is 6.8 amperes, determine: i. Neglect leakage. (K.U.) Example 11. An iron ring of mean length 1 meter has an air gap of 2 mm and a winding 400 turns. If the permeability of the iron is 400 when a current of 2.5 amperes flow through flow through the coil, find the flux density. Indore University) Solution. Mean length of iron ring (or iron path), l i 1 m (neglecting air gap length) Length of air gap. Number of turns, N 400 Permeability of iron, r 400 Current through the coil, I 2.5 A Flux density, B Total AT required AT required for iron ring (AT i )AT required for air gap (AT g ) i.e. AT AT i AT g H i l i H g l g Example 12. An iron ring of mean circumference of 900 mm and cross-sectional area: of 250 mm 2 has flux of 500 Wb. Find the flux in the ring if the m.m.f. A relative permeability of 1200 may be assumed. Roorkee University) Solution. Given: l i 900 2 898 0.898 m; A 250 mm 2 250 10 -6 m 2 500 Wb 500 x 10 -6 Wb; 19 2 mm 0.002 m; r 1200. Before the air gap is cut: Example 13. A ring his a diameter of 24 cm and a cross-sectional area of 1000 mm 2. The ring is made up of semicircular sections of cast iron and cast steel with each joint having a reluctant equal to an air gap of 0.2 mm. Find the ampere-turns required to produce a flux of 8 10- 4 Wb. The relative permeability of caststeel and cast iron are 900 and 170 respectively. Neglect fringing and leakage effects. Gujarat University) Solution. Given: 8 10 -4 Wb A 1000 mm 2 1000 10 -6 0.001 m 3 Total length of air gap, l g 2 0.2 0.4 mm 0.0004 m ( r ) c.s. Example 14. A magnetic ring has a mean circumference of 1.8 m and is of 0.012 m 2 cross-section, and is wound with 210 turns.
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